Java: Variables are Always Passed by Copy
I am learning Java. One important concept to understand is whether function arguments are passed by copy or by reference.
Passing by copy means that when a variable is passed to a function, a copy of that variable is made. Passing by reference means that the code in the function operates on the original variable, not on a copy.
In Java, variables are always passed by copy. Let’s explore this through three scenarios:
Case 1: Passing Primitives
void incrementValue(int inFunction) {
inFunction++;
System.out.println("In function: " + inFunction);
}
int original = 10;
System.out.println("Original before: " + original);
incrementValue(original);
System.out.println("Original after: " + original);
The result is:
Original before: 10
In function: 11
Original after: 10
The original value didn’t change.
Case 2: Passing Primitives Wrapped in Objects
void incrementValue(int[] inFunction){
inFunction[0]++;
System.out.println("In function: " + inFunction[0]);
}
int[] arOriginal = {10, 20, 30};
System.out.println("Original before: " + arOriginal[0]);
incrementValue(arOriginal);
System.out.println("Original after: " + arOriginal[0]);
The result is:
Original before: 10
In function: 11
Original after: 11
The original value did change! This happens because complex object variables are references. A reference variable points to a location in memory. When a variable is passed to a function, a new reference is always created. Both references point to the original object or value.
int[] original = {10, 20, 30};
original[0] --> | 10 | <-- inFunction[0]
| 20 |
| 30 |
Both array elements point to the same memory location.
Case 3: Passing Strings
void changeString(String inFunction){
inFunction = "New!";
System.out.println("In function: " + inFunction);
}
String original = "Original!";
System.out.println("Original before: " + original);
changeString(original);
System.out.println("Original after: " + original);
The result is:
Original before: Original!
In function: New!
Original after: Original!
Remember, Strings are immutable. When passed to a function, a new String is created, leaving the original String unaltered.